It is not a 6-parameter function, it is a family of 3d-functions each characterized by 3 parameters. Those parameters can be modified using the dropdown in the top-right corner of the page.
The Hamiltonian is an operator that describes the energy of a system. Eigenfunctions of the Hamiltonian are quantum states, referred to as wave functions. The squared amplitude of a wave function is a probability distribution function. When discussing the wave functions of electrons, the probability amplitude is sometimes referred to as the electron density. You are looking at a sampling from the electron density of the wave functions of the 1-electron 1-nucleus Hamiltonian operator. There are different wave functions (different entries in the dropdown box at the top-right corner of the screen) because the Hamiltonian operator has more than one eigenfunction. Each eigenfunction is characterized by the 3 "quantum numbers": n, l, and m. "n" indicates the number of radial nodes -- areas of a given distance from the nucleus where the electron density is 0. "l" indicates the number of angular nodes -- areas arranged in a certain angular pattern around the nucleus where the electron density is 0.
> I think there is something that would truly help: if one would take a volume integral over a infinitesimal cube of the 3D interactive representation, what physical units would the result be in?
Number of electrons (possibly fractional, if you aren't sampling the whole space). For this particular Hamiltonian, the integral over all space should be numerically 1 for any given eigenfunction, since we are looking at the 1-electron Hamiltonian.
> It is not a 6-parameter function, it is a family of 3d-functions each characterized by 3 parameters. Those parameters can be modified using the dropdown in the top-right corner of the page.
Sorry to be pedantic, but these two things are the exact same thing.
You were asking how it is to be interpreted, and it is as I said: a family of 3D functions each characterized by 3 parameters. What you are saying is technically correct, but misses the point of what I was trying to convey.
Edit: also, three of the parameter (x, y, z or r, θ, φ depending on whether you are using a Cartesian or spherical coordinate system) are continuous, real, and unbounded (well, unbounded in a Cartesian sense anyway). In contrast, n, l, and m are discrete integer-valued quantum coefficients that obey the relations n > 0, 0 <= l < n, -l <= m <= l.
The Hamiltonian is an operator that describes the energy of a system. Eigenfunctions of the Hamiltonian are quantum states, referred to as wave functions. The squared amplitude of a wave function is a probability distribution function. When discussing the wave functions of electrons, the probability amplitude is sometimes referred to as the electron density. You are looking at a sampling from the electron density of the wave functions of the 1-electron 1-nucleus Hamiltonian operator. There are different wave functions (different entries in the dropdown box at the top-right corner of the screen) because the Hamiltonian operator has more than one eigenfunction. Each eigenfunction is characterized by the 3 "quantum numbers": n, l, and m. "n" indicates the number of radial nodes -- areas of a given distance from the nucleus where the electron density is 0. "l" indicates the number of angular nodes -- areas arranged in a certain angular pattern around the nucleus where the electron density is 0.
> I think there is something that would truly help: if one would take a volume integral over a infinitesimal cube of the 3D interactive representation, what physical units would the result be in?
Number of electrons (possibly fractional, if you aren't sampling the whole space). For this particular Hamiltonian, the integral over all space should be numerically 1 for any given eigenfunction, since we are looking at the 1-electron Hamiltonian.